graphing a line

**Noelle** · November 14th 2007, 12:58 PM

Graph the line.
2) Through (0, 6), m = 15 1 over 5

**topsquark** · November 14th 2007, 02:47 PM

Originally Posted by Noelle

Graph the line.
2) Through (0, 6), m = 15 1 over 5

Whaaat? Please tell us the question as it is written.

I get that you want a line through the point (0, 6). And that you are given the slope. But what is "15 1 over 5"?

-Dan

**Noelle** · November 14th 2007, 03:08 PM

Graph the line.
2) Through (0, 6), m = 1 (rise) over 5 (run) so 1 over 5

**earboth** · November 15th 2007, 05:45 AM

Originally Posted by Noelle

Graph the line.
2) Through (0, 6), m = 1 (rise) over 5 (run) so 1 over 5

Hello,

I assume that the slope of the line is $m=\frac15$

Use the point-slope-formula. If you know the coordinates of point $P(x_1, y_1)$ and the slope m then the equation of the line is:

$y-y_1=m(x-x_1)$ . Plug in the values you already know and solve for y. $(y = \frac15 \cdot x+6)$

Second attempt: The general form of an equation of a straight line is:

$y=mx+b$ . The coordinates of the given point must satisfy this equation. You know m already. Plug in these values and solve for b:

$6=\frac15 \cdot 0 +b~\iff~b = 6$

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