f(x)= x^2+16x+62?
I did the quadratic formula and got:
-4, -12
No, your answers are not correct. A simple way to check is to "plug" in your answer for x in f(x) and see if f(x)=0, if it is true then the variable subbed in is a corresponding zero.
Quadratic Equation Solver
You do not show your work so how can we possibly tell where you made a mistake. Finding the zeroes of a quadratic using the quadratic formula is the right procedure, but clearly you did not apply the formula correctly.
$(-\ 4)^2 + 16(-\ 4) + 62 = 16 + 62 - 64 = 14 \ne 0.$
$(-\ 12)^2 + 16(-\ 12) + 62 = 144 + 62 - 192 = 14 \ne 0.$