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Math Help - Coordinate geometry question

  1. #1
    Newbie hymnseeker's Avatar
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    Coordinate geometry question

    Just a really quick one, suppose I have a line of equation: y=1/2x+5/2

    The next part of the question asks for this in the form of ax+by+c=0

    How do I convert from y=mx+c to ax+by+c=0?

    Thank youuu!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by hymnseeker View Post
    Just a really quick one, suppose I have a line of equation: y=1/2x+5/2

    The next part of the question asks for this in the form of ax+by+c=0

    How do I convert from y=mx+c to ax+by+c=0?

    Thank youuu!
    bring everything to one side and leave 0 on the other side and (in this case) multiply through by 2 when done
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  3. #3
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    Thanks for the reply, so just let y=0?

    1/2x+5/2=0

    Does this satisfy what the question wants in asking for ax+by+c=0?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by hymnseeker View Post
    Thanks for the reply, so just let y=0?

    1/2x+5/2=0

    Does this satisfy what the question wants in asking for ax+by+c=0?
    did you read what i said? i said bring everything over to one side, how does that translate to equating y to zero?

    y = \frac 12x + \frac 52 ............subtract y from both sides

    \Rightarrow 0 = \frac 12x - y + \frac 52 ...............multiply through by 2

    \Rightarrow 0 = x - 2y + 5

    which is the same thing as

    x - 2y + 5 = 0


    here a = 1, b = -2 and c = 5
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  5. #5
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    Thank you for your help. Needed to see it visually - and in answer to your question (although I suspect it was rhetorical), yes, I did read what you said first off.
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by hymnseeker View Post
    Thank you for your help. Needed to see it visually - and in answer to your question (although I suspect it was rhetorical), yes, I did read what you said first off.
    yes, it was rhetorical. you're welcome, and good luck with your class
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