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Math Help - Need help with these problems.

  1. #1
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    Unhappy Need help with these problems.

    tan^-1 sqrt3/3

    sec^-1>1< (not eleven)

    csc^-1(-sqrt2)

    cot^-1(-sqrt3)


    I have missed so much school and don't really know what to do. If you could help me out I would really appreciate it
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  2. #2
    Senior Member sakonpure6's Avatar
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    Re: Need help with these problems.

    Quote Originally Posted by Korototo View Post
    tan^-1 sqrt3/3

    sec^-1>1< (not eleven)

    csc^-1(-sqrt2)

    cot^-1(-sqrt3)


    I have missed so much school and don't really know what to do. If you could help me out I would really appreciate it
    Hello Korototo!


    For problem:

    a) Just use a scientific calculator, find the tan button and locate the 2nd function button on the calculator, press the 2nd function button then the tan button then open parentheses and type (sqrt3/3) then hit equal. Also note that sqrt3/3 = 1/sqrt3 (check with calculator for proof, or multiply (1/sqrt3) by (sqrt3/sqrt3) ), which is the ratio of tan 30 degrees in this special 30–60–90 degrees triangle Need help with these problems.-trig_30_60_90.gif and based on the image provided, the angle 30 satisfies tan^-1 (1/sqrt3).

    b) I am not sure I understand the question, can you verify it please.

    c)csc (x) is equal to sin (1/x) . Therefor, csc^-1 (sqrt2) = sin^-1 (1/sqrt2) , same principal as in part a): Use a calculator or NOTE that sqrt2 is part of another special triangle: Need help with these problems.-150px-45-45-triangle.svg.png and based on the diagram I gave you, the angle 45 satisfies this problem since sine is opp/hyp, and the ratio of angle 45 (sin) is 1 /sqrt2 .

    d) You should try this question using a calculator and the special triangles I provided. Hint cot (x) = tan (1/x)

    If you have more questions please ask!
    Last edited by sakonpure6; February 23rd 2014 at 06:57 PM.
    Thanks from mash and HallsofIvy
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