I am trying to put the equations into standard form of a conic section...

But cannot find its factors properly i have those three equations left

Show all steps please...

Thanks

1. 3x^2-y^2+9x+8y-145/4=0

2. 4x^2+9y^2+24x+18y+12=0

3. y^2+10y=2x-1

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- Nov 12th 2007, 03:30 PMxterminal01[SOLVED] Equation into standard form of a conic
I am trying to put the equations into standard form of a conic section...

But cannot find its factors properly i have those three equations left

Show all steps please...

Thanks

1. 3x^2-y^2+9x+8y-145/4=0

2. 4x^2+9y^2+24x+18y+12=0

3. y^2+10y=2x-1

- Nov 12th 2007, 08:31 PMtopsquark
- Nov 12th 2007, 11:25 PMxterminal01
Thank you I appreciate it,

I have tried to do the # 2 and 3 myself and this is what i came up with

2. 4x^2+9y^2+24x+18y+12=0

4x^2+9y^2+24x+18y=-12

4(x^2+6x+9)+9(y^2+2y+1)=-12+36+9

4(x+3)^2 + 9(y+1)^2 = 33

(x+3)^2 + (y+1)^2

33 33 = 1

4 9

and # 3 i guess is a parabola and this is what i got

y^2+10y=2x-1

(y^2+10y+25) = 2x-1+25

(y+5)^2 = 2x + 24

(y+5)^2 = 2(x+12)

Please let me know if i did the rest correct :) - Nov 13th 2007, 12:23 AMearboth