# Urgent Polar etc. coordinates

• Jan 7th 2014, 06:42 PM
orange
Urgent Polar etc. coordinates
• Jan 7th 2014, 07:02 PM
HallsofIvy
Re: Urgent Polar etc. coordinates
If it is so urgent, have you not tried anything yourself? Did you not see that this is part of a circle? It is the part of a circle of radius 6 beyond radius 2. What is the area of a circle of radius 6? What is the area of a circle of radius 2? " $2\le r\le 6$" is the area of the "washer" with inner radius 2 and outer radius 6. And $\frac{5\pi}{6}- \frac{\pi}{3}= \frac{5\pi}{6}- \frac{2\pi}{6}= \frac{3\pi}{6}= \frac{\pi}{2}$, a quarter of a circle.
• Jan 7th 2014, 07:20 PM
orange
Re: Urgent Polar etc. coordinates
Thank you. So you subtract the littlest circle from the biggest one and divide by 4?
• Jan 9th 2014, 09:43 AM
HallsofIvy
Re: Urgent Polar etc. coordinates
Yes.