This is of the form ab - ac = a(b-c) (the distributive law). In this case a = (x-2)^2, b = (x-2), c = 1 which means it reduces to a(b-c) = (x-2)^2(x-2-1) = (x-2)^2(x-3)
Hi guys and gals,
I am reading schaums outline of precalculus 2nd ed. and I am having some issues solving a problem.
Can someone point me to a tutorial that can help me factor equations like this:
They give you the answer of (x-2)^2(x-3) but I don't understand how they got there.
holy cow... thanks for the fast response. I feel like a deer in headlights looking at your math. I will do my best to understand this but I still cant quite grasp it. I am a very visual learner... do you think there are any youtube videos on this?