Hello, Fnus!

Here's the first one . . .

The point (-2,3) is on the graph.has a stationary point at

(a) Find the values of and

(b) Find the position and nature of all stationary points.

. . Hence: . .[1]

Since (-2,3) is a stationary point,

. . and we have: .

Substitute into [1]: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

The function is: .

Then: .

When . . . Critical point:

When . . . Critical point:

Second Derivative Test: .

. . . concave up . . . minumum at

. . . concave down . . . maximum at