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Math Help - Equation of Perpendicular Bisector

  1. #1
    Senior Member nycmath's Avatar
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    Equation of Perpendicular Bisector

    Find the equation of the line that is the perpendicular bisector of the segment joining the points (2,1) and (6,7). Write answer in the form Ax+By+C = 0.

    I found the slope of the given points to be 3/2.

    I then found the midpoint of the two given points to be (4,4).

    I then calculated the slope of the perpendicular bisector to be -2/3.

    I then plugged (-2/3) and the midpoint (4,4) into the point-slope formula and ended up with the equation y = (-2/3)x + (20/3).

    I finally expressed the above equation as (2/3)x + y - (20/3) = 0.

    The book's answer is
    2x + 3y - 20 = 0

    What are the right steps to find the equation given as the answer in the book?
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  2. #2
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    Re: Equation of Perpendicular Bisector

    Multiply your answer by three. It is correct, just not in the form they want.
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  3. #3
    Senior Member nycmath's Avatar
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    Re: Equation of Perpendicular Bisector

    I found the right equation by multiplying both sides of the equation by 3. How about that?
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    Re: Equation of Perpendicular Bisector

    yeah, that's what I was saying!
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  5. #5
    Senior Member nycmath's Avatar
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    Re: Equation of Perpendicular Bisector

    I will post one more tonight. I worked on it but just cannot find the correct equation. Look for my next question in 5 minures. Thanks again....
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  6. #6
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    Re: Equation of Perpendicular Bisector

    Use a different forum thread
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