# Thread: Equation of Perpendicular Bisector

1. ## Equation of Perpendicular Bisector

Find the equation of the line that is the perpendicular bisector of the segment joining the points (2,1) and (6,7). Write answer in the form Ax+By+C = 0.

I found the slope of the given points to be 3/2.

I then found the midpoint of the two given points to be (4,4).

I then calculated the slope of the perpendicular bisector to be -2/3.

I then plugged (-2/3) and the midpoint (4,4) into the point-slope formula and ended up with the equation y = (-2/3)x + (20/3).

I finally expressed the above equation as (2/3)x + y - (20/3) = 0.

2x + 3y - 20 = 0

What are the right steps to find the equation given as the answer in the book?

2. ## Re: Equation of Perpendicular Bisector

Multiply your answer by three. It is correct, just not in the form they want.

3. ## Re: Equation of Perpendicular Bisector

I found the right equation by multiplying both sides of the equation by 3. How about that?

4. ## Re: Equation of Perpendicular Bisector

yeah, that's what I was saying!

5. ## Re: Equation of Perpendicular Bisector

I will post one more tonight. I worked on it but just cannot find the correct equation. Look for my next question in 5 minures. Thanks again....