# Trig question pre calc!

• October 26th 2013, 02:13 AM
Gurp925
Trig question pre calc!
Hi there, the question states

Prove algebraically: $\cos\theta/1-sin\theta$ = $sec\theta +(sec\theta)(csc\theta)-cot\theta$

Here are the steps i took to solving this i worked on the right side making it equal the left

1) change all sec/ csc/ cot to their respective forms ( $\1/sin\theta)$ and so forth

and when i get to this point I'm lost $\frac{sin\theta +1 - cos\theta^2} {cos\theta sin\theta}$

After this point I'm lost please help, i apologize if i have asked too many questions but i am trying to study for my final.

Thanks!
• October 26th 2013, 02:15 AM
chiro
Re: Trig question pre calc!
Hey Gurp925.

Is it meant to be cos(theta) / [1 - sin(theta)] or cos(theta) - sin(theta)?
• October 26th 2013, 03:48 AM
acc100jt
Re: Trig question pre calc!
$\frac{sin\theta+1-cos^2\theta}{cos\theta sin\theta}$

$=\frac{sin\theta+sin^2\theta}{cos\theta sin\theta}$

$=\frac{sin\theta(1+sin\theta)}{cos\theta sin\theta}$

$=\frac{1+sin\theta}{cos\theta}$

$=\frac{(1+sin\theta)(1-sin\theta)}{cos\theta(1-sin\theta)}$

$=\frac{1-sin^2\theta}{cos\theta(1-sin\theta)}$

$=\frac{cos^2\theta}{cos\theta(1-sin\theta)}$

...

Hope this helps :)
• October 26th 2013, 10:29 AM
Gurp925
Re: Trig question pre calc!
Hey Acc100jt almost understood the question just wondering how did you multiply the denominator by (1-sin) ?thus multiplying the top? if i understand that then the question is solved. Thanks everyone for their help.
• October 26th 2013, 03:45 PM
Prove It
Re: Trig question pre calc!
Quote:

Originally Posted by Gurp925
Hey Acc100jt almost understood the question just wondering how did you multiply the denominator by (1-sin) ?thus multiplying the top? if i understand that then the question is solved. Thanks everyone for their help.

Multiplying top and bottom by the bottom's conjugate.