I need help with this word problem:

If you stand in shallow water and look at an object below the surface of the water, the object will look farther away from you than it really is. This is because when light rays pass between air and water, the water refracts, or bends, the light rays. The index of refraction for water is 1.333. This is ratio of the sine of theta1 and the sine of theta2

a)You are standing in water that is 2 feet deep and are looking at a rock at angle

theta1 =60 degrees(measurement from a line perpendicular to the surface of the water). Find theta2.

b)Find the distance x and y

c)Find the distance d between where the rock is and where it appears to be.

d)What happens to d as you move closer to the rock? Explain you reasoning.

Here's a picture to help: