Question: What are the possible values of |2x−3| when 0<|x−1|<2?
We know∣∣x−1∣∣becomes x-1 if x-1≥0 and -(x-1) if x-1<0.
Now consider two cases.
Then the possible value include |2x-3|<3. Am I solving this problem correctly ??
Note, -5<|2x-3|<-1 would not work since the |2x-3| is bounded between two negative values.
Am I solving this problem correctly ?? The solution seems so incomplete?