# Math Help - Functional Transformations

1. ## Functional Transformations

Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1?

2. ## Re: Functional Transformations

horizontal shrink would be ((1/2)x)^3

3. ## Re: Functional Transformations

Originally Posted by votan
horizontal shrink would be ((1/2)x)^3
Thank you so much!

I spent like 5 hours trying to figure this out!!!!!!1

4. ## Re: Functional Transformations

Originally Posted by votan
horizontal shrink would be ((1/2)x)^3
But then how do you make the distinction between $f\left(\tfrac{1}{2}x\right)$ and $\tfrac{1}{8} f(x)$ if $f(x) = x^3$? Or indeed, in OP's question, between $f\left(\tfrac{1}{2^{1/3}}x\right)$ and $\tfrac{1}{2} f(x)$?

OP, don't hold me to this, but I think the transformation acts as both but I'm not 100% sure.