Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1?

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- Sep 21st 2013, 06:35 PMGragadoodleFunctional Transformations
Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1? - Sep 21st 2013, 06:59 PMvotanRe: Functional Transformations
horizontal shrink would be ((1/2)x)^3

- Sep 21st 2013, 07:02 PMGragadoodleRe: Functional Transformations
- Sep 22nd 2013, 02:55 PMFelixFelicis28Re: Functional Transformations