# Functional Transformations

• Sep 21st 2013, 05:35 PM
Functional Transformations
Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1?
• Sep 21st 2013, 05:59 PM
votan
Re: Functional Transformations
horizontal shrink would be ((1/2)x)^3
• Sep 21st 2013, 06:02 PM
Re: Functional Transformations
Quote:

Originally Posted by votan
horizontal shrink would be ((1/2)x)^3

Thank you so much!

I spent like 5 hours trying to figure this out!!!!!!1
• Sep 22nd 2013, 01:55 PM
FelixFelicis28
Re: Functional Transformations
Quote:

Originally Posted by votan
horizontal shrink would be ((1/2)x)^3

But then how do you make the distinction between $\displaystyle f\left(\tfrac{1}{2}x\right)$ and $\displaystyle \tfrac{1}{8} f(x)$ if $\displaystyle f(x) = x^3$? Or indeed, in OP's question, between $\displaystyle f\left(\tfrac{1}{2^{1/3}}x\right)$ and $\displaystyle \tfrac{1}{2} f(x)$?

OP, don't hold me to this, but I think the transformation acts as both but I'm not 100% sure.