Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1?

Printable View

- September 21st 2013, 05:35 PMGragadoodleFunctional Transformations
Why is f(x) = 1/2 (x^3) a vertical shrink?

Isn't is supposed to be a horizontal stretch, because f(x) = f(cx), 0<c<1? - September 21st 2013, 05:59 PMvotanRe: Functional Transformations
horizontal shrink would be ((1/2)x)^3

- September 21st 2013, 06:02 PMGragadoodleRe: Functional Transformations
- September 22nd 2013, 01:55 PMFelixFelicis28Re: Functional Transformations