Determine an equation in factored form for the polynomial represented by the graph.

Graph #1: Image - TinyPic - Free Image Hosting, Photo Sharing & Video Hosting

Looking at this I can say:

>4 degree polynomial; Quartic

>Zero's: -1, +1, 2

>Even Degree Polynomial

>Point at: (0,4)

y= a (x+1) (x-1) (x-2)

...plug in (0,4) -> 4=a(0+1)(0-1)(0-2) -> 2=a

y=2(x+1)(x-1)(x-2)................Is this answer correct? Shouldn't this have been an Even Degree Polynomial?(Also just making sure, is this in factored form?)

Graph #2. Image - TinyPic - Free Image Hosting, Photo Sharing & Video Hosting

Looking at this I can say:

>4 Degree Polynomial (minimum); Quartic

>Zero's: -2, +1

>Point at: (0,-2)

y=a (x+2) (x-1)

...plug in (0,-2) -> -2=a (0+2)(0-1) -> 0=a -> ?

y=(x+2)(x-1)......................I'm certain this is unfinished/incorrect

.........................................Since a=0, and no other point in defined on the graph...? I don't know how I would solve this?