http://puu.sh/3K86l.jpg

i cannot finish 1 c) and d)... that is how far i got.

i am having some problems with turning trinomials with no common factors into binomials

thank you

Printable View

- Jul 23rd 2013, 04:19 PMMathnood768rational expressions #2
http://puu.sh/3K86l.jpg

i cannot finish 1 c) and d)... that is how far i got.

i am having some problems with turning trinomials with no common factors into binomials

thank you - Jul 23rd 2013, 05:16 PMadkinsjrRe: rational expressions #2
In (c) just find the roots of the quadratic equation you're trying to factor, which are 4 and . So one factor would have to be and the other would have to be . Try something similar to the other problem you're working on.

- Jul 23rd 2013, 05:57 PMSorobanRe: rational expressions #2
Hello, Mathnood768!

You need more Factoring practice.

Quote:

Factor and reduce: .

Quote:

. .

. . - Jul 23rd 2013, 06:06 PMMathnood768Re: rational expressions #2
thank you!

- Jul 23rd 2013, 06:11 PMMathnood768Re: rational expressions #2
why is it not 2/y - 2 though? why do you say its negative?

- Jul 23rd 2013, 06:29 PMHallsofIvyRe: rational expressions #2
The minus comes from the 3- 4y in the original problem. In order to be able to cancel with the 4y- 3 which is a factor , Soroban factored out a "-1" writing it as -(4y- 3).