I have an interval for a certain function. -1<4x^2<1 How do I solve for x with the negative on the left? Thanks
Follow Math Help Forum on Facebook and Google+
Originally Posted by minneola24 I have an interval for a certain function. $\displaystyle -1<4x^2<1$ How do I solve for x with the negative on the left? That tells you that $\displaystyle |x|<\sqrt{\frac{1}{4}}$ That also answers your question about the radius of convergence.
Since $\displaystyle 4x^2$ cannot be negative, "$\displaystyle -1< 4x^2<1$" is the same as "$\displaystyle 0\le 4x^2< 1$".
View Tag Cloud