1. ## Quick algebra question

I have an interval for a certain function.

-1<4x^2<1

How do I solve for x with the negative on the left?

Thanks

2. ## Re: Quick algebra question

Originally Posted by minneola24
I have an interval for a certain function.

$\displaystyle -1<4x^2<1$

How do I solve for x with the negative on the left?
That tells you that $\displaystyle |x|<\sqrt{\frac{1}{4}}$

3. ## Re: Quick algebra question

Since $\displaystyle 4x^2$ cannot be negative, "$\displaystyle -1< 4x^2<1$" is the same as "$\displaystyle 0\le 4x^2< 1$".