I have an interval for a certain function.

-1<4x^2<1

How do I solve for x with the negative on the left?

Thanks

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- Jul 14th 2013, 12:35 PMminneola24Quick algebra question
I have an interval for a certain function.

-1<4x^2<1

How do I solve for x with the negative on the left?

Thanks - Jul 14th 2013, 01:07 PMPlatoRe: Quick algebra question
- Jul 15th 2013, 08:14 AMHallsofIvyRe: Quick algebra question
Since $\displaystyle 4x^2$ cannot be negative, "$\displaystyle -1< 4x^2<1$" is the same as "$\displaystyle 0\le 4x^2< 1$".