solve in R:

http://mathramz.com/xyz/latexrender/...1c796b7463.png

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- July 5th 2013, 01:31 AMdhiabno solution
- July 5th 2013, 01:40 AMchiroRe: no solution
Hey dhlab.

What have you tried?

Hint: Try using the rational roots theorem to see if you can get a possibility of a rational root first off. - July 5th 2013, 01:41 AMProve ItRe: no solution
Write it as with , which can be solved using the Quartic Formula. Then solve for ...

- July 5th 2013, 03:31 AMibduttRe: no solution
- July 5th 2013, 07:55 AMProve ItRe: no solution
I didn't say Quadratic Formula, I said Quartic Formula.

I suggest you read this: - July 5th 2013, 11:50 AMdhiabRe: no solution
I suggest this solution

http://www.mathmontada.net/vb/upload...373049942.docx - July 5th 2013, 05:22 PMHallsofIvyRe: no solution
What do you

**mean**by saying " ? It certainly**is**equal to 0 or some values of x.

(You are**correct**that is never 0 and that is all you need to show that the sum is not 0.) - July 5th 2013, 08:48 PMibduttRe: no solution
by using x = y = B/4 we get

( y+1)^4 - 4 ( y+1)^3 + 8(y+1)^2 + 3 = 0

y^4+2y^2 +8y+8=0

(y^2+1)^2 = 8y -7

How do we proceed from hereonward