On checking we find tat for this equation we will not get the answer given. please check if the question has been correctly pasted.
http://puu.sh/3kEIh.png
My attempt: I wrote it down on paper and I have nothing I could use to take a picture of, I'm not sure how I can write it out but:
square both sides to get rid of the radical sign on the left side then use FOIL on right side.
q^2/2 + 11 = q^2 - 2q + 2
multiply 2
q^2 - 4q - 18
then i put it into the quadratic formula, q^2 = a -4 = b -18 = c
after that, I ended up with http://puu.sh/3kEO7.png
the answer for this question is suppose to be q = 2 + 2(sqrt(6))
i don't know how to get the right answer.
this question solved is suppose to be q = 2 + 2(sqrt(6)) {apparently that is the correct answer}
but I get http://puu.sh/3kEO7.png
Hello, Mathnood768!
You're making a number of blunders . . .
Square both sides: .
. . . . . . . . . . . . . . . . . . .
Multiply by 2: . . . . . . . . .
. . . . . . . . . . . . . . . .
Quadratic Formula: .
. . . . . . . . . . . . . . .
But we find that. ndoes not check.
. . It is an extraneous root.
The only root is: .