I threw this equation into Mathway, but the answer wasn't correct. I have two tries at the question, so looking for some help. The equation is as follows:
(x-10)(x+3)(x-2)^2 < 0
Hint: Try looking at values left and right of the zeroes (i.e. 10, -3, and 2) and see when you get a negative or a positive answer.
Then use this to get the regions when < 0 and you're done. (For example if f(x) = (x-10)(x+3)(x-2)^2 and f(1) < 0 then the interval [-3,2] is <= 0 since 1 is between -3 and 2).