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Math Help - Logarithm Using Givens (without calculator)

  1. #1
    Junior Member ReneG's Avatar
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    Logarithm Using Givens (without calculator)

    Given \log 2 = 0.3010 and \log 3 = 0.4771 find \log_5{512}

    I was only able to simplify to 9\log_5{2}, but I don't know what to do. I tried using the change of base formula, but that left me with \log 5 which I couldn't compute algebraically
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    Re: Logarithm Using Givens (without calculator)

    Quote Originally Posted by ReneG View Post
    Given \log 2 = 0.3010 and \log 3 = 0.4771 find \log_5{512}

    I was only able to simplify to 9\log_5{2}, but I don't know what to do. I tried using the change of base formula, but that left me with \log 5 which I couldn't compute algebraically
    I think that there is a typo in the statement of the question.

    I think the 5 should be a 3.
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    Junior Member ReneG's Avatar
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    Re: Logarithm Using Givens (without calculator)

    I wish that was the case, but it's not.
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    Re: Logarithm Using Givens (without calculator)

    Quote Originally Posted by ReneG View Post
    I wish that was the case, but it's not.
    Then that problem cannot be done. But I am willing to bet it is a typo.
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    Junior Member ReneG's Avatar
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    Re: Logarithm Using Givens (without calculator)

    I've figured it out \log_5{512} = \frac{9\log 2}{\log{10} - \log 2} = \frac{9(0.3010)}{1-0.3010}

    I didn't need log 3 to solve it though.
    Last edited by ReneG; June 16th 2013 at 07:16 PM.
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    Forum Admin topsquark's Avatar
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    Re: Logarithm Using Givens (without calculator)

    Quote Originally Posted by ReneG View Post
    I didn't need log 3 to solve it though.
    Nice work! However since you didn't need the log(3) I'm skeptical...

    -Dan
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