This gives , which is correct.

Dividing both the numerator and the denominator by , we have

now this gives me 2.

What's wrong?

P.S. I tested the values on a calculator.

Printable View

- June 16th 2013, 01:17 AMHeilKingLimit problem (what's going wrong?)

This gives , which is correct.

Dividing both the numerator and the denominator by , we have

now this gives me 2.

What's wrong?

P.S. I tested the values on a calculator. - June 16th 2013, 04:36 AMPlatoRe: Limit problem (what's going wrong?)
Do not double post.

You can be banded for that. - June 18th 2013, 08:08 PMmpx86Re: Limit problem (what's going wrong?)

first it can be written as

now you cannot take x out since it is a**negative number**

this question can be done in the following way

since x is negative , convert it to a positive number by substituting y= -x or x= -y

therefore functon becomes

thus answer is infinity not minus infinity......