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I have done the first 2 questionf of 8 but I cannot do the last 2,

I don't know what to do so I haven't attempted anything...

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- Jun 15th 2013, 08:03 PMMathnood768Dividing Radicals #2
imgur: the simple image sharer

I have done the first 2 questionf of 8 but I cannot do the last 2,

I don't know what to do so I haven't attempted anything... - Jun 15th 2013, 10:37 PMCesc1Re: Dividing Radicals #2
Remember that

$\displaystyle \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

With that in mind you can express

$\displaystyle \sqrt{\frac{5}{12}}$ as $\displaystyle \frac{\sqrt{5}}{\sqrt{12}}$ and solve part c) as you did in parts a) and b)

For part d) you can do something similar, but notice that here we have a cube root.

Try to solve it and let us know if you need more help. - Jun 15th 2013, 11:35 PMibduttRe: Dividing Radicals #2
- Jun 16th 2013, 05:24 PMMathnood768Re: Dividing Radicals #2
what do i do with the -2/3???

- Jun 16th 2013, 07:59 PMibduttRe: Dividing Radicals #2
Firstly it is 2/3 and not - 2/3 [ 1 - 1/3 = 2/3 ]

- Jun 16th 2013, 08:05 PMibduttRe: Dividing Radicals #2