When we look at the range as given, it depends on the value of sin 2 theta. and maximum value that sine of an angle is 1. Use this to get answer to your question
A baseball hit at an angle θ above the horizontal and with initial velocity v0 has range R given by R = ((velocity^2) / g))(sin 2θ) , where 0 ≤ θ ≤ π/2 . What angle gives the maximum range? What is the maximum range?
I haven't come across a problem like this, but using what I already know, I'm thinking the angle that gives the maximum range would be π/3. I'm not really sure how to answer the question though. Any advice?