Find the equation of the tangent to the curve y = 2 - e^-x at the point where x =1.
I know that you have to find the derivative of that function, which is dy/dx = e^-x
I don't really know how to get the answer beyond that though, because the answer is: x - ey + 2e - 2 = 0
The equation is not in the form of "y=mx+b" and I'm not sure how to find the above answer. If any suggestions or tests can be provided, it would be much appreciated. Please and thank you!