How can i solve this problem! rectangles

Hi, How's everything guys?!

Guys i have a problem with a basic math question:D

**Question:** Length of a rectangle is equal to **[2x+1]** and Width of the rectangle is equal to** [x+5]** Calculate the perimeter and area of the rectangle in terms of x.

Please help me guys:D** I Solve it but i think my answer is wrong!**

**please cheack it:x:x:x**

Length : 2x+1

Width : x+5

Perimiter : 2(2x+1+x+5) => 2(3x +6) => 6x + 12 => x= 6/12 => **x=2**

Area: (2x+1).(x+5) => (3x+ 10x + x + 5) => (14x + 5) => **x = 5/14**

Re: How can i solve this problem! rectangles

Quote:

Originally Posted by

**miladceph** **please cheack it:x:x:x**

Length : 2x+1

Width : x+5

Perimiter : 2(2x+1+x+5) => 2(3x +6) => 6x + 12 => x= 6/12 => **x=2**

Area: (2x+1).(x+5) => (3x+ 10x + x + 5) => (14x + 5) => **x = 5/14**

For the perimeter calculation you were doing great for both of these right up til the last statement. You have:

Perimeter = 6x + 12.

That's the answer right there, as it defines the perimter in terms of x, so no need to go on! Your next move was to say that x = 12/6, but that's wrong. Applying basic algebra you might have said this:

Perimter = 6x+12

6x = Perimeter - 12

x = Perimter/6 - 2

But that simply gives x in terms of the perimter, but that's not what they're asking.

As for the area calculation you didn't multiply the two terms correctly. Area = (2x+1)(x+5) = 2x(x+5) + 1(x+5) = 2x^2 +10x + x + 5 = 2x^2 +11x + 5.