Hey elittlewood.
Did you mean (m^2+2m-3)*a + (m^2+m-6)*b = 0?
If so try setting up equations involving m and each of the vector components (i.e. x, y, and z) and then solve a set of equations.
Hi , not sure if vectors falls under this category , but what are you going to do I just need someone to explain this question for me step by step if you have time . I'm Gavin quite a hard time with it :/
"The vectors a and b span two space . For what values of m is it true that (m^2+2m-3)a + (m^2+m-6) = 0
*note that it is a 0 vector. I imagine this'd and they have to cancel each other out some how but I don't know how ....
Thanks !
Emma
Basically you have x,y,z for a and another for b.
You will get three sets of three equations. For example if we look only at x co-ordinate, we get:
(m^2 + 2m - 3)*x_a - (m^2 + m - 6)x_b = 0.
You have two other equations involving the other co-ordinates so if you set x_a and x_b to constants you can solve for m and if m is a common solution for all co-ordinates, then you have a solution.
Please note that there is no second b in the original post. I think there is a typo in the question itself.
I have seen this sort of question before. I think it should be .
Because span 2-space then .
Thus coordinates really have little to do with it.