$\displaystyle \ln(x^2)=10$

I know how to solve this by turning it into an exponential form ie.

$\displaystyle e^{10}=x^2$

and solving from there but can you do something like this

$\displaystyle e^{\ln(x^2)}=e^{10}$

$\displaystyle e^{2\ln(x)}=e^{10}$

I don't know what to do from here.