Solve the triangle. B = 36°, a = 41, c = 17 choices are b ≈ 29, C ≈ 20, A ≈ 124 b ≈ 44, C ≈ 20, A ≈ 124 b ≈ 29, C ≈ 121, A ≈ 23 b ≈ 44, C ≈ 24, A ≈ 120
Follow Math Help Forum on Facebook and Google+
These look like test questions.. So all I will put is this: $\displaystyle b^2 = a^2 + c^2 - 2acCos(B)$ Where angle B is opposite side b
Last edited by Bradyns; May 14th 2013 at 09:01 PM.
View Tag Cloud