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Math Help - Radicals #2

  1. #1
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    Radicals #2

    imgur: the simple image sharer

    My attempt:

    imgur: the simple image sharer

    I was really close, that 8 is suppose to be a 12, could I have gone somewhere in the factoring tree? I'm not sure....
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  2. #2
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    Re: Radicals #2

    For mercury you got to ^3\sqrt{193600}= ^3\sqrt{3025\times 2^6}= ^3\sqrt{3025} \times ^3\sqrt{2^{6}}

    Remember you are taking the cube root so ^3\sqrt{2^{6}}=2^2
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  3. #3
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    Re: Radicals #2

    Quote Originally Posted by Shakarri View Post
    For mercury you got to ^3\sqrt{193600}= ^3\sqrt{3025\times 2^6}= ^3\sqrt{3025} \times ^3\sqrt{2^{6}}

    Remember you are taking the cube root so ^3\sqrt{2^{6}}=2^2
    Just an FYI about the LaTeX code:
    [tex]\sqrt[3]{2^6}[/tex]

    gives
    \sqrt[3]{2^6}

    -Dan
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    Re: Radicals #2

    Thank you!
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