# Math Help - Radicals #2

imgur: the simple image sharer

My attempt:

imgur: the simple image sharer

I was really close, that 8 is suppose to be a 12, could I have gone somewhere in the factoring tree? I'm not sure....

For mercury you got to $^3\sqrt{193600}= ^3\sqrt{3025\times 2^6}= ^3\sqrt{3025} \times ^3\sqrt{2^{6}}$

Remember you are taking the cube root so $^3\sqrt{2^{6}}=2^2$

Originally Posted by Shakarri
For mercury you got to $^3\sqrt{193600}= ^3\sqrt{3025\times 2^6}= ^3\sqrt{3025} \times ^3\sqrt{2^{6}}$

Remember you are taking the cube root so $^3\sqrt{2^{6}}=2^2$
Just an FYI about the LaTeX code:
$$\sqrt[3]{2^6}$$

gives
$\sqrt[3]{2^6}$

-Dan