imgur: the simple image sharer

My attempt:

imgur: the simple image sharer

I was really close, that 8 is suppose to be a 12, could I have gone somewhere in the factoring tree? I'm not sure....

Printable View

- May 12th 2013, 11:07 AMMathnood768Radicals #2
imgur: the simple image sharer

My attempt:

imgur: the simple image sharer

I was really close, that 8 is suppose to be a 12, could I have gone somewhere in the factoring tree? I'm not sure.... - May 12th 2013, 02:29 PMShakarriRe: Radicals #2
For mercury you got to $\displaystyle ^3\sqrt{193600}= ^3\sqrt{3025\times 2^6}= ^3\sqrt{3025} \times ^3\sqrt{2^{6}}$

Remember you are taking the cube root so $\displaystyle ^3\sqrt{2^{6}}=2^2$ - May 12th 2013, 05:17 PMtopsquarkRe: Radicals #2
- May 13th 2013, 06:44 PMMathnood768Re: Radicals #2
Thank you!