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Math Help - Radicals #1

  1. #1
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    Post Radicals #1

    imgur: the simple image sharer

    My attempt:

    imgur: the simple image sharer

    I'm not sure if I was right about dividing .3 in the beginning from the radical.
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  2. #2
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    Re: Radicals #1

    You didn't need to divide by 0.3. You also divided 6.3 by 0.3 as well as dividing \sqrt{48} by \sqrt{0.3} so in total you divided by 0.3\sqrt{0.3}. If you want to do this you also have to multiply by 0.3\sqrt{0.3} to effectively multiply by 1 so that you don't change the value of it, to balance things.

    Also there is no need bring everything inside the square root so that it is \sqrt{70560} because you'll end up bringing it all outside the square root in the end.
    You can simplify it like this
    6.3\sqrt{48}= 6.3\sqrt{6\times8}=6.3\sqrt{2\times3\times2\times2  \times2}= 6.3\times 2\times 2\sqrt{3}=25.2\sqrt{3}
    Somehow your answer still came out right
    Thanks from topsquark and Mathnood768
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  3. #3
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    Re: Radicals #1

    Thank you!
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