Hi there the question is Solve log6(x-1)+log6(x+4)=2 I dont get any solutions i cant factor it.
and the second one is log2(2x+4)+log2(x-1)=3 I get 2.5 as answer.
lastly log_{a}(x - 3)(x + 4) + log_{a}x = log_{a}5
Thanks ahead of time.
Hi there the question is Solve log6(x-1)+log6(x+4)=2 I dont get any solutions i cant factor it.
and the second one is log2(2x+4)+log2(x-1)=3 I get 2.5 as answer.
lastly log_{a}(x - 3)(x + 4) + log_{a}x = log_{a}5
Thanks ahead of time.
I can not understand fully your question, because you do not use proper mathematical symbols. But, I will try to answer it.
a)$\displaystyle \log_{6}{(x-1)} + \log_{6}{(x+4)} = \log_{6}{36} \Leftrightarrow \\ \Leftrightarrow \log_{6}{[(x-1)(x+4)]} = \log_{6}{36} \Leftrightarrow \\ \Leftrightarrow (x-1)(x+4) = 36 \quad etc... \quad The \quad others \quad are \quad exactly \quad the \quad same$