Hi there the question is Solve log6(x-1)+log6(x+4)=2 I dont get any solutions i cant factor it.

and the second one is log2(2x+4)+log2(x-1)=3 I get 2.5 as answer.

lastly log_{a}(x - 3)(x + 4) + log_{a}x = log_{a}5

Thanks ahead of time.

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- May 4th 2013, 11:14 PMGurp925Need Help Math homework >.<
Hi there the question is Solve log6(x-1)+log6(x+4)=2 I dont get any solutions i cant factor it.

and the second one is log2(2x+4)+log2(x-1)=3 I get 2.5 as answer.

lastly log_{a}(x - 3)(x + 4) + log_{a}x = log_{a}5

Thanks ahead of time. - May 5th 2013, 12:40 AMGurp925Re: Need Help Math homework >.<
Sorry there is one more logsqrt2(x-2)+logsqrt2(x+1)=4

- May 5th 2013, 01:08 AMManosGRe: Need Help Math homework >.<
I can not understand fully your question, because you do not use proper mathematical symbols. But, I will try to answer it.

a)$\displaystyle \log_{6}{(x-1)} + \log_{6}{(x+4)} = \log_{6}{36} \Leftrightarrow \\ \Leftrightarrow \log_{6}{[(x-1)(x+4)]} = \log_{6}{36} \Leftrightarrow \\ \Leftrightarrow (x-1)(x+4) = 36 \quad etc... \quad The \quad others \quad are \quad exactly \quad the \quad same$ - May 5th 2013, 10:30 PMGurp925Re: Need Help Math homework >.<
That equation does not factor so what to do?

- May 5th 2013, 10:42 PMMarkFLRe: Need Help Math homework >.<
Distribute (FOIL) the left side, then subtract through by 36, and you will have a quadratic that factors nicely...and be mindful of the domain of the log functions...