Divide through by 2 first, then convert from exponential to logarithmic form.
If you take the natural log of both sides, you have:
Same as if you had just divided through by 2 initially.
I have an assignment question looks like this
I figured, first time around, that I could just apply natural logarithm to both, and get
and then x = ln(5)/-4
This does not result in the correct answer.
Why? I can get the correct answer (by dividing both sides by two initially)
If I have 2e^(-2x) and apply the natural logarithm to it, what does it become?
Divide through by 2 first, then convert from exponential to logarithmic form.
If you take the natural log of both sides, you have:
Same as if you had just divided through by 2 initially.