Creating a straight line equation from a logarithm equation?

Show that the equation relating the magnetic force kx^n to the component of the moveable magnet’s

component of weight along the incline is mg sin θ = kx^n, where m = 0.05 kg is the mass of each

magnet, k is a constant, and g = 9.8 m/s2 is the acceleration due to gravity

Ok so I have a set of values,

sintheta

.05

.1

.15

.2

.25

.30

x(cm)

14.1

9.8

8.2

7

6.4

5.6

The equation that relates them is mgsintheta = kx^n

now I hit both sides with log

log (mgsintheta) = nlog(x) + log(k)

My question is how do I create x and y values that I can plot on a graph. I assume the x(cm) is on my x-axis but I'm confused what goes on my y-axis.

Is it just log(.5) or is it log((9.8*.05*sin(.5)) for the y values?

Re: Creating a straight line equation from a logarithm equation?

Quote:

Originally Posted by

**llama** Show that the equation relating the magnetic force kx^n to the component of the moveable magnet’s

component of weight along the incline is mg sin θ = kx^n, where m = 0.05 kg is the mass of each

magnet, k is a constant, and g = 9.8 m/s2 is the acceleration due to gravity

And **what** is $\displaystyle \theta$, the angle the incline makes with the horizontal?

Quote:

Ok so I have a set of values,

sintheta

.05

.1

.15

.2

.25

.30

x(cm)

14.1

9.8

8.2

7

6.4

5.6

The equation that relates them is mgsintheta = kx^n

now I hit both sides with log

log (mgsintheta) = nlog(x) + log(k)

My question is how do I create x and y values that I can plot on a graph. I assume the x(cm) is on my x-axis but I'm confused what goes on my y-axis.

Is it just log(.5) or is it log((9.8*.05*sin(.5)) for the y values?

These are values you got from a lab?

You want a linear equation of the form y= Ax+ b so take $\displaystyle y= log(mgsin(\theta)$, $\displaystyle x= log(x)$, NOT x, and $\displaystyle b= log(k)$

Re: Creating a straight line equation from a logarithm equation?

Right Theta is the incline with the horizontal.

Sorry I couldn't quite understand the last thing you wrote. It had a bunch of weird characters my computer didn't feel like loading lol

So I have my y and x axis,

I find out y value from y=log(mgsintheta) and i find my X values from x=log(x) ?

and then my slope is N, and my y-intercept is log(k)?