And that's it!

Results 1 to 5 of 5

- April 21st 2013, 07:07 PM #1

- Joined
- Sep 2012
- From
- lockport
- Posts
- 10

## Log or ln

My problem is 2^3x=3^x+4

i have been trying this problem and have done or gotten this far.. i dont know if its right or wrong but....

3x ln2= x+4 ln3

3 ln2 + x ln2 = x ln 3 + 4 ln 3

x ln 2 - x ln 3 = 4 ln 3 - 3 ln 2

x ln 2/3 = ? ln 3/2

this is what i got and im stumped am i on the right track and or what is the next step..

any help is appreciated

- April 21st 2013, 07:51 PM #2

- April 21st 2013, 07:56 PM #3

- Joined
- Jul 2012
- From
- INDIA
- Posts
- 849
- Thanks
- 216

- April 22nd 2013, 01:50 AM #4

- Joined
- Apr 2012
- From
- Erewhon
- Posts
- 203
- Thanks
- 134

## Re: Log or ln

What you have posted is meaningless; If you are going to post in ASCII learn to use parentheses to make your expressions unambiguous.

The helpers have assumed you mean:

which is not unreasonable given what follows, but that is not what you have posted means under the usual conventions which may be:

or even

etc..

.

- April 22nd 2013, 05:28 AM #5

- Joined
- Sep 2012
- From
- lockport
- Posts
- 10