Ted popped a baseball straight up with an initial upward velocity of 48 ft/s. The height, h, in feet, of the ball above the ground is modeled by the function h(t) = 3 + 48t - 16t^2. How long was the ball in the air if the catcher catches the ball 3 ft above the ground? Is your answer reasonable?
h(t) = 3 + 48t - 16t^2
3(t) = 3 + 48t - 16t^2
This is how much I have done, I'm not sure if I did that right, I think I need to isolate t, but I do not know how to do that algebraically.