1. ## Writing Equations - Quadratics

The product of two consecutive even integers is 16 more than 8 times the smaller integer? Determine the integers.

How can I write an equation out of this? I have never done this yet. Would it be in the form of ax^2 + bx + c = 0 ? I don't really know how to do this question because how it is worded...

2. ## Re: Writing Equations - Quadratics

You can let one of the integer be x and then get an expression in term of x for the other one. If the integers are consecutive, then if the smaller is x, the other is x+1. Then, by taking the product and adding the constants, you should be able to get an equation solvable for x, the smaller integer.

I hope this helps.

3. ## Re: Writing Equations - Quadratics

I still need help with this question...

4. ## Re: Writing Equations - Quadratics

Set x(x+2) = 8x+16. (Sorry, in the previous post I mistakenly wrote x+1. Since the two integers are consecutive even, their difference is 2)

Then, by rearranging the two sides you get:

x^2-6x-16=0.

Solve this equation and you will get the answer for x. The other integer is just x+2.

5. ## Re: Writing Equations - Quadratics

x^2 - 6x - 16 = 0

x^2 - 8x + 2x - 16

(x - 8) (x + 2)

x = 8 x = -2

The answer is suppose to be 8 and 10 or 0 and -2