# Math Help - Solving for parameter

1. ## Solving for parameter

given x= sec t or and y= tan t how do you solve for t in each equation?

2. Hello, googoogaga!

Given: . $\begin{array}{c}x\:= \:\sec t \\ y\: = \:\tan t\end{array}$
I believe you are trying to "eliminate the parameter".

Square both equations: . $\begin{array}{cc}x^2 \:=\:\sec^2\!t & [1]\\ y^2 \:=\:\tan^2\!t & [2]\end{array}$

Subtract [2] from [1]: . $x^2-y^2\:=\:\sec^2\!t - \tan^2\!t$

Therefore: . $x^2-y^2\:=\:1$