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Math Help - Solving for parameter

  1. #1
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    Solving for parameter

    given x= sec t or and y= tan t how do you solve for t in each equation?
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  2. #2
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    Hello, googoogaga!

    Given: . \begin{array}{c}x\:= \:\sec t \\ y\: = \:\tan t\end{array}
    I believe you are trying to "eliminate the parameter".


    Square both equations: . \begin{array}{cc}x^2 \:=\:\sec^2\!t & [1]\\ y^2 \:=\:\tan^2\!t & [2]\end{array}

    Subtract [2] from [1]: . x^2-y^2\:=\:\sec^2\!t - \tan^2\!t

    Therefore: . x^2-y^2\:=\:1

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