Quick question about Taylor Polymonials

Quick question:

When they ask for the 'fifth' term of a particular taylor polymonial, which term are they asking for?

Eg. If I had the McLauren series for $\displaystyle e^x = 1 + \dfrac{x}{1!} + \dfrac{x^2}{2!} + \dfrac{x^3}{3!} + \dfrac{x^4}{4!} + \dfrac{x^5}{5!} + \dfrac{x^6}{6!} + ...$

Do they mean the fifth one $\displaystyle \dfrac{x^4}{4!}$ or do they mean the x^5 term?

Re: Quick question about Taylor Polymonials

Since the polynomial starts with $\displaystyle x^0$, the fifth term is $\displaystyle x^4$.

Re: Quick question about Taylor Polymonials

What if the Taylor polynomial has zero coefficient terms in it? Eg.

$\displaystyle 1 - \dfrac{x^2}{2!} + \dfrac{x^4}{4!} - \dfrac{x^6}{6!} + ...$

Would the third term be $\displaystyle \dfrac{x^4}{4!}$