# Thread: Horizontal, Vertial, & Oblique Asymptote?

1. ## Horizontal, Vertial, & Oblique Asymptote?

So my precal assignment is asking me to find the vertical, horizontal, and oblique asymptotes.

I got to the following problem.
R(X) = 3x+5/x-6

Would the horizontal asymptote be y=3 & vertical asymptote be x=1?

2. ## Re: Horizontal, Vertial, & Oblique Asymptote?

First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?

3. ## Re: Horizontal, Vertial, & Oblique Asymptote?

Originally Posted by HallsofIvy
First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?
To be completely honest I'm lost. Would it be -6 since x+6 = 0?

4. ## Re: Horizontal, Vertial, & Oblique Asymptote?

Originally Posted by Supernatural
So my precal assignment is asking me to find the vertical, horizontal, and oblique asymptotes.

I got to the following problem.
R(X) = 3x+5/x-6

Would the horizontal asymptote be y=3 & vertical asymptote be x=1?
R(x) = (3x + 5)/(x - 6)

the function would be undefined at (x-6) = 0, this might occur only when x = 6

checking the numerator we have x = -5/3 the critical point, and seems to be the vertical asymptote for this function, check it...