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Math Help - Horizontal, Vertial, & Oblique Asymptote?

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    Horizontal, Vertial, & Oblique Asymptote?

    So my precal assignment is asking me to find the vertical, horizontal, and oblique asymptotes.

    I got to the following problem.
    R(X) = 3x+5/x-6

    Would the horizontal asymptote be y=3 & vertical asymptote be x=1?
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    Re: Horizontal, Vertial, & Oblique Asymptote?

    First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?
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    Re: Horizontal, Vertial, & Oblique Asymptote?

    Quote Originally Posted by HallsofIvy View Post
    First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?
    To be completely honest I'm lost. Would it be -6 since x+6 = 0?
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    Re: Horizontal, Vertial, & Oblique Asymptote?

    Quote Originally Posted by Supernatural View Post
    So my precal assignment is asking me to find the vertical, horizontal, and oblique asymptotes.

    I got to the following problem.
    R(X) = 3x+5/x-6

    Would the horizontal asymptote be y=3 & vertical asymptote be x=1?
    R(x) = (3x + 5)/(x - 6)

    the function would be undefined at (x-6) = 0, this might occur only when x = 6

    checking the numerator we have x = -5/3 the critical point, and seems to be the vertical asymptote for this function, check it...
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