First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?
First, what you wrote would normally be interpreted as 3x+ (5/x)- 6 but i suspect you mean (3x+ 5)/(x- 6). Yes, y= 3 is the only horizontal asymptote. But the vertical asymptote is NOT x= 1. How did you get that?