Eliminate the parameter.
x = t^{2} + 1, y = t^{2} - 1
Hello, ambitionty9!
$\displaystyle \text{Eliminate the parameter. }\:\begin{Bmatrix} x &=& t^2+1 & [1]\\ y &=& t^2-1 & [2] \end{Bmatrix}$
Subtract [2] - [1]: .$\displaystyle y-x \:=\:-2 \quad\Rightarrow\quad y \:=\:x-2$
The graph is a straight line.
It starts at $\displaystyle t=0\!:\;\;(x,y) \,=\,(1,\text{-}1)$
Code:| | * + * | * - - + - + - * - + - - | * 2 + * | . -2. . | |