# Math Help - Log and e problem

1. ## Log and e problem

If I have ln(elne) do I solve this as

lne + lne = 1 +1 = 2

or

ln(lnee) = ln(e) = 1

2. ## Re: Log and e problem

The first variant should say ln(e) + ln(ln(e)) = 1 + ln(1) = 1 + 0 = 1. The second variant is correct.

3. ## Re: Log and e problem

You could just treat it like this.

Equation (1)
$ln(eq)$, where $q=ln(e)$

Given that,
$q=ln(e)\Rightarrow q= 1$

Equation (1) can be rewritten as:
$ln(eq) \Rightarrow ln(1e) \Rightarrow ln(e) = 1$