# Log and e problem

• April 8th 2013, 12:56 PM
Quixotic
Log and e problem
If I have ln(elne) do I solve this as

lne + lne = 1 +1 = 2

or

ln(lnee) = ln(e) = 1
• April 8th 2013, 01:03 PM
emakarov
Re: Log and e problem
The first variant should say ln(e) + ln(ln(e)) = 1 + ln(1) = 1 + 0 = 1. The second variant is correct.
• April 20th 2013, 12:03 AM
$ln(eq)$, where $q=ln(e)$
$q=ln(e)\Rightarrow q= 1$
$ln(eq) \Rightarrow ln(1e) \Rightarrow ln(e) = 1$