$\displaystyle \lim_{x \rightarrow {\frac{\pi}{4}}}{\frac{1+cos2x}{(\pi-2x)^2}$ in this problem I replace all x by $\displaystyle \frac{\pi}{4}$ finally i get the answer like this $\displaystyle \frac{4}{\pi^2}$.Is this answer is correct or not????
$\displaystyle \lim_{x \rightarrow {\frac{\pi}{4}}}{\frac{1+cos2x}{(\pi-2x)^2}$ in this problem I replace all x by $\displaystyle \frac{\pi}{4}$ finally i get the answer like this $\displaystyle \frac{4}{\pi^2}$.Is this answer is correct or not????