$\displaystyle \lim_{x \rightarrow {\frac{\pi}{4}}}{\frac{1+cos2x}{(\pi-2x)^2}$ in this problem I replace all x by $\displaystyle \frac{\pi}{4}$ finally i get the answer like this $\displaystyle \frac{4}{\pi^2}$.Is this answer is correct or not????

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- Mar 24th 2013, 07:43 AMsrirahulanLiMiTs
$\displaystyle \lim_{x \rightarrow {\frac{\pi}{4}}}{\frac{1+cos2x}{(\pi-2x)^2}$ in this problem I replace all x by $\displaystyle \frac{\pi}{4}$ finally i get the answer like this $\displaystyle \frac{4}{\pi^2}$.Is this answer is correct or not????

- Mar 24th 2013, 08:02 AMmajaminRe: LiMiTs
Yes, that's correct.