# Thread: vertical and horizontal shifts, answer provided - just need to understand method :)

1. ## vertical and horizontal shifts, answer provided - just need to understand method :)

I have the answer from the back of the book on these but have no idea how they get to that point. Any help is greatly appreciated!

Write a formula and graph the transformations of m(n) = (1/2)n^2

1. y = m(n+1)
2. y = m(n-3.7)

1. (1/2)n^2 + n + (1/2)
2. (1/2)n^2 - 3.7n + 6.845

Thank you!!

2. ## Re: vertical and horizontal shifts, answer provided - just need to understand method

I got my answer, thank you!!

3. ## Re: vertical and horizontal shifts, answer provided - just need to understand method

Do you see why the following is true?

$\displaystyle y=m(n+1)=\frac{1}{2}(n+1)^2$
$\displaystyle y=m(n-3.7)=\frac{1}{2}(n-3.7)^2$

Now use $\displaystyle (a+b)^2=a^2+2ab+b^2$ to expand the terms.

4. ## Re: vertical and horizontal shifts, answer provided - just need to understand method

Originally Posted by Gusbob
Do you see why the following is true?

$\displaystyle y=m(n+1)=\frac{1}{2}(n+1)^2$
$\displaystyle y=m(n-3.7)=\frac{1}{2}(n-3.7)^2$

Now use $\displaystyle (a+b)^2=a^2+2ab+b^2$ to expand the terms.
Yes! Thank you!!