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Math Help - vertical and horizontal shifts, answer provided - just need to understand method :)

  1. #1
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    vertical and horizontal shifts, answer provided - just need to understand method :)

    I have the answer from the back of the book on these but have no idea how they get to that point. Any help is greatly appreciated!

    Write a formula and graph the transformations of m(n) = (1/2)n^2

    1. y = m(n+1)
    2. y = m(n-3.7)

    Answers:
    1. (1/2)n^2 + n + (1/2)
    2. (1/2)n^2 - 3.7n + 6.845

    Thank you!!
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  2. #2
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    Re: vertical and horizontal shifts, answer provided - just need to understand method

    I got my answer, thank you!!
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  3. #3
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    Re: vertical and horizontal shifts, answer provided - just need to understand method

    Do you see why the following is true?

    y=m(n+1)=\frac{1}{2}(n+1)^2
    y=m(n-3.7)=\frac{1}{2}(n-3.7)^2

    Now use (a+b)^2=a^2+2ab+b^2 to expand the terms.
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  4. #4
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    Re: vertical and horizontal shifts, answer provided - just need to understand method

    Quote Originally Posted by Gusbob View Post
    Do you see why the following is true?

    y=m(n+1)=\frac{1}{2}(n+1)^2
    y=m(n-3.7)=\frac{1}{2}(n-3.7)^2

    Now use (a+b)^2=a^2+2ab+b^2 to expand the terms.
    Yes! Thank you!!
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