I have a circuit diagram of 5 switches.
Reliability of switch A and B are 99.5%
while C,D and E are 98%.
What is the reliability of the circuit working?
I understand how to do a straight circuit multiplying the percents such as A and B being .995 * .995= .99025 or 99.025% but seeing how this circuit spreads out I am having a hard time finding the equations I must do and put together in order to find the percent if reliability. I do understand with all these switches the percent of reliability must be extremely high and close to 100%.
Anything will help at this point. Thanks!
Here's what I got:
P(A & B) = (0.995)(0.995) = 0.990025
P(D||E)=1-(1-0.98)(1-0.98) = 0.9996
P(C&D||E)= 0.98(0.9996) = 0.979608
P(A & B || C & D|| E) = 1-(1-0.990025)(1-0.979608)=0.9998